Chemistry - GENERAL CHEMISTRY Question with Solution | TestHub

ChemistryGENERAL CHEMISTRYElectronic ConfigurationMedium2 minQB

ChemistryMediummultiple choice

Choose the correct options from the following :-

Answer:

A, D

Solution:

Configurations: Cr ( $Z = 24$ ) is $[A r] 3 d^{5} 4 s^{1}$ and S ( $Z = 16$ ) is $[N e] 3 s^{2} 3 p^{4}$ .

Option (A): Both have 6 valence electrons ( $3 d + 4 s$ for Cr and $3 s + 3 p$ for S), so this is correct.

Option (D): Cr belongs to Group 6 (d-block) and S belongs to Group 16 (p-block), making this correct.

Incorrect Options: (B) is false because Cr has 6 unpaired electrons while S has only 2; (C) is false as Cr is in Period 4 and S is in Period 3.

Stream:JEESubject:ChemistryTopic:GENERAL CHEMISTRYSubtopic:Electronic Configuration

⏱ 2mℹ️ Source: QB

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