Consider the following pairs of electrons
(A) $n = 3, l = 1, m_{l} = 1, m_{s} = + \frac{1}{2}$
(B) $n = 3, l = 2, m_{l} = - 2, m_{s} = - \frac{1}{2}$
(C) $n = 4, l = 2, m_{l} = 2, m_{s} = + \frac{1}{2}$
The pairs of electrons present in degenerate orbitals is/are

Question

Consider the following pairs of electrons

(A) $n = 3, l = 1, m_{l} = 1, m_{s} = + \frac{1}{2}$
(B) $n = 3, l = 2, m_{l} = - 2, m_{s} = - \frac{1}{2}$
(C) $n = 4, l = 2, m_{l} = 2, m_{s} = + \frac{1}{2}$

The pairs of electrons present in degenerate orbitals is/are

TestHub · Accepted Answer

The orbitals which have same energy are called degenerate orbitals. Energy or an orbital depends on two quantum numbers, principle quantum number (n) and azimuthal quantum number (l).

The orbitals with similar values of $n & l$ but with different value of $m$ will be degenerate orbitals.

Among the given set or orbital only option (B) fulfil this condition.

Chemistry - GENERAL CHEMISTRY Question with Solution | TestHub

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