Chemistry - GENERAL CHEMISTRY Question with Solution | TestHub

As per$\left(\text{n}+\text{l}\right)$rule electrons fill first in that orbital which have least$\left(\text{n}+\text{l}\right)$value.
When$\left(\text{n}+\text{l}\right)$values are same, then electron fills that orbital which have lowest$\text{n}$value.
when$\text{n}=6$as per$\left(\text{n}+\text{l}\right)$rule when$\text{n}=6$
$\text{ns}$subshell$\Rightarrow 6+0=6$

$\left(\text{n}-1\right)\text{d}$subshell$\Rightarrow 5+2=7$

$\left(\text{n}-2\right)\text{f}$subshell$\Rightarrow 4+3=7$

$\text{np}$subshell$\Rightarrow 6+1=7$

$\mathrm{n}\mathrm{s}\mathrm{ },\mathrm{ }\left(\mathrm{n}-2\right)\mathrm{f},\mathrm{ }\left(\mathrm{n}-1\right)\mathrm{d},\mathrm{n}\mathrm{p}$

$\left(\mathrm{n}+\mathcal{l}\right)\mathrm{ }\mathrm{v}\mathrm{a}\mathrm{l}\mathrm{u}\mathrm{e}\mathrm{s}\mathrm{ }\Rightarrow 7,\mathrm{ }7,\mathrm{ }7\mathrm{ }$

$\mathrm{n}\mathrm{ }\mathrm{v}\mathrm{a}\mathrm{l}\mathrm{u}\mathrm{e}\mathrm{ }\Rightarrow 4,\mathrm{ }5,\mathrm{ }6$