Chemistry - GENERAL CHEMISTRY Question with Solution | TestHub

Electronic configuration of$\mathrm{R}{\mathrm{b}}_{\left(37\right)}$is
$1{\mathrm{s}}^{2}2{\mathrm{s}}^{2}2{\mathrm{p}}^{6}3{\mathrm{s}}^{2}3{\mathrm{p}}^{6}3{\mathrm{d}}^{10}4{\mathrm{s}}^{2}4{\mathrm{p}}^{6}5{\mathrm{s}}^1$
So, for the valence shell electron$\left(5{\mathrm{s}}^1\right)$
$\mathrm{n}=5,\mathrm{}\mathrm{}\mathrm{l}=0,\mathrm{}\mathrm{}\mathrm{m}=0,\mathrm{}\mathrm{}\mathrm{s}=+\frac{1}{2}$