Chemistry - GENERAL CHEMISTRY Question with Solution | TestHub

ChemistryGENERAL CHEMISTRYElectronic ConfigurationMedium2 minPYQ_2019

ChemistryMediumsingle choice

The $71^{st}$ electron of an element $X$ with an atomic number of $71$ enters the orbital:

Answer:

Solution:

$_{71} Lu : [Xe] 4 f^{14} 6 s^{2} 5 d^{1}$ (The last electron enters $5 d$ orbital)

Stream:JEESubject:ChemistryTopic:GENERAL CHEMISTRYSubtopic:Electronic Configuration

⏱ 2mℹ️ Source: PYQ_2019

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