Chemistry - GENERAL CHEMISTRY Question with Solution | TestHub

Electronic configuration of $\mathrm{N}$ 

$\left[\mathrm{He}\right]2{\mathrm{s}}^2, 2{\mathrm{p}}^3$

The correct configuration of '$\mathrm{N}$' is,

According to Hunds' rule, the electron first singly occupied in parallel, then anti-parallel in any particular orbital. In the given option, the last electron of $\mathrm{P}-$orbital is in downwards spin. So, option $1$ is incorrect.

Orbital angular momentum of any orbital, 

$$\begin{gathered} \mathrm{L}=\sqrt{\mathrm{l} \left( \mathrm{l}+1 \right)}. \frac{\mathrm{h}}{2\mathrm{\pi }} \\ \mathrm{For} \mathrm{S}-\mathrm{orbital}, \mathrm{l} \mathrm{value} =0 \\ \mathrm{So}, \mathrm{L} = 0 \end{gathered}$$