Not considering the electronic spin, the degeneracy of the second excited state (n = 3 ) of H atom is 9 , while the degeneracy of the second excited state of H - is :

Question

TestHub · Accepted Answer

Energy order of orbitals of H is decided by only principle quantum number (n) while energy order of $H^{-}$ is decided by $(n + l)$ rule:
Electronic configuration of $' H^{-}'$ is $- 1 s^{2}$ its energy order is decided by $n + l$ rule.
$H^{-} = 1 s^{2} 2 s^{0} 2 p^{0}$
Its $2^{n d}$ excited state is 2p
And degeneracy $2 p is 3$ .

Chemistry - GENERAL CHEMISTRY Question with Solution | TestHub

Doubts & Discussion