Chemistry - f-block Question with Solution | TestHub

The$+3$oxidation state of lanthanide is most stable and therefore lanthanide in$+4$oxidation state has strong tendency to gain${\mathrm{e}}^{-}$and converted into$+3$and therefore act as strong oxidizing agent.$e.g. {\mathrm{Ce}}^{+4}$And therefore${\mathrm{CeO}}_2$is used to oxidized alcohol aldehyde and ketones. Lanthanide in$+2$oxidation state has strong tendency to loss${\mathrm{e}}^{-}$and converted into$+3$oxidation state therefore act as strong reducing agent.$\therefore {\mathrm{EuSO}}_4$act as strong reducing agent.