Chemistry - f-block Question with Solution | TestHub

$\text{Yb}={\left[\text{Xe}\right]}^{54}4{\text{f}}^{14}5{\text{d}}^{0}6{\text{s}}^2$
$\mathrm{Y}{\mathrm{b}}^{2+}=\left[\mathrm{X}\mathrm{e}\right]4{\mathrm{f}}^{14}$
As n = 0 so diamagnetic.
As in rest other there are unpaired electron/s so they are paramagnetic.