Chemistry - f-block Question with Solution | TestHub

The electronic configuration of Uranium is,
$\left[\mathrm{R}\mathrm{n}\right]\mathrm{ }5{\mathrm{f}}^3\mathrm{ }6{\mathrm{d}}^{1}7{\mathrm{s}}^2$

Hence, the maximum electrons it can lose is$3+1+2=6$(Inner electrons do not come out due to stability)

The electronic configuration of plutonium is,$\left[\mathrm{R}\mathrm{n}\right]\mathrm{ }5{\mathrm{f}}^6\mathrm{ }7{\mathrm{s}}^2$

It exhibits a maximum oxidation state of$+7$.