Chemistry - Mole Concept Question with Solution | TestHub
3.00 gm of an organic compound containing C, H, O, S, and N only, is burnt completely by excess of oxygen gas (O₂). The gaseous product is first cooled to room temperature, by which water vapor is condensed and absorbed completely by anhydrous CaCl₂. The mass of the salt increased by 2.16 gm. Now, the remaining gases were passed through excess of aqueous NaOH solution, by which the mass of the solution increased by 5.68 gm. The gases that remained were passed through excess alkaline pyrogallol solution. The gas still present occupied 150 ml at 1.642 atm and 27°C. In another experiment, 6.00 gm of the same organic compound produced 9.32 gm BaSO₄, after treatment with a series of non-sulfur reagents (Ba = 137).
On combustion , the mole ratio of and formed is -
Options:
Answer:
Solution:
Find moles of SO₂: From the second experiment, 6.00 g of compound yields of BaSO₄ (), so 3.00 g yields of S, producing () of SO₂.
Find moles of CO₂: The NaOH solution absorbs both CO₂ and SO₂; thus, mass of CO₂ = .
Calculate CO₂ moles: Moles of CO₂ = .
Determine the ratio: The mole ratio , which simplifies to 5:1 (Option C).