The solubility product of a sparingly soluble salt $A_{2} X_{3}$ is $1.1 \times 1 0^{- 23}$ .
If specific conductance of the solution is $3 \times 1 0^{- 5} S m^{- 1}$ , the limiting molar conductivity of the solution is $x \times 1 0^{- 3} S m^{2} mol^{- 1}$ . The value of $x$ is $____$ .

Question

The solubility product of a sparingly soluble salt $A_{2} X_{3}$ is $1.1 \times 1 0^{- 23}$ .

If specific conductance of the solution is $3 \times 1 0^{- 5} S m^{- 1}$ , the limiting molar conductivity of the solution is $x \times 1 0^{- 3} S m^{2} mol^{- 1}$ . The value of $x$ is $____$ .

TestHub · Accepted Answer

A 2 ​ X 3 ( s ) ​ ⇌ 2 A ( a q ) + 3 ​ + 3 X ( a q ) − 2 ​ 2s3s ( 2 s ) 2 ( 3 s ) 3 108 s 5 s N o w Λ m ​ ⇒ Λ m ∞ ​ ​ = 1.1 × 1 0 − 23 = 1.1 × 1 0 − 23 ≃ 1 0 − 5 M = 1 0 − 5 L mol ​ = 0.01 m 3 mol ​ ≃ Λ m ∞ ​ = m k ​ = s k ​ = 0.01 3 × 1 0 − 5 ​ = 3 × 1 0 − 3 S ⋅ m 2 / m o l ​

Chemistry - Electrochemistry Question with Solution | TestHub

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