Assertion: If A 2 + + e − ⟶ A + ; E ∘ = x A + + e − ⟶ A ; E ∘ = y Hence, for A 2 + + 2 e − ⟶ A , E ∘ = x + y . Reason: E ∘ is an intensive property.

E° is an intensive property, so it's not additive. Use Δ G ∘ = − n F E ∘ for additivity.

Chemistry - Electrochemistry Question with Solution | TestHub

ChemistryElectrochemistryRelationship between Eº, DGº & KeqMedium2 minQB

ChemistryMediumassertion reason

Assertion: If $A^{2 +} + e^{-} ⟶ A^{+}$ ; $E^{\circ} = x$

$A^{+} + e^{-} ⟶ A$ ; $E^{\circ} = y$

Hence, for $A^{2 +} + 2 e^{-} ⟶ A$ , $E^{\circ} = x + y$ .

Reason: $E^{\circ}$ is an intensive property.

Answer:

Solution:

E° is an intensive property, so it's not additive. Use $Δ G^{\circ} = - n F E^{\circ}$ for additivity.

Stream:JEESubject:ChemistryTopic:ElectrochemistrySubtopic:Relationship between Eº, DGº & Keq

⏱ 2mℹ️ Source: QB

Loading discussions...