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Chemistry - Electrochemistry Question with Solution | TestHub

ChemistryElectrochemistryGalvanic cells/Nernst Equation/Concentration CellsMedium2 minQB

ChemistryMediumsingle choice

For the cell $Hg ∣ Hg_{2} Cl_{2} ∣ Cl^{-} (0.1 M) ∥ Cl^{-} (0.01 M) ∣ Cl_{2} ∣ Pt, E^{o}$ is 1.10 V . Hence, E is

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Answer:

Solution:

The Nernst equation calculates E: $E = E^{\circ} - \frac{0.0591}{n} lo g Q$ . Here, $E = 1.10 - \frac{0.0591}{2} lo g \frac{[ C l ^{-} ] _{an o d e}^{2}}{[ C l ^{-} ] _{c a t h o d e}^{2}} = 1.159 V$ .

Stream:JEESubject:ChemistryTopic:ElectrochemistrySubtopic:Galvanic cells/Nernst Equation/Concentration Cells

⏱ 2mℹ️ Source: QB

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