In the preparation of chlorine gas by the electrolysis of sodium hydroxide solution, the Δ G ∘ value for the following reaction is + 482.5 k J . 2 C l ( a q ) − + 2 H 2 O ( l ) ⟶ H 2 ( g ) + C

Question

In the preparation of chlorine gas by the electrolysis of sodium hydroxide solution, the $Δ G^{\circ}$ value for the following reaction is $+ 482.5 k J$ .

$2 C l_{(a q)}^{-} + 2 H_{2} O_{(l)} ⟶ H_{2 (g)} + C l_{2 (g)} + 2 O H_{(a q)}^{-}$

The voltage required to make the reaction feasible by considering the $Δ G^{\circ}$ value negative is:

TestHub · Accepted Answer

​ Δ G 0 = − n F E 0 ​ ​ ​ E 0 = nF − Δ G 0 ​ = ( 2 mol ) ( 9.65 × 1 0 4 J / mol V ) 4.825 × 1 0 5 J ​

Chemistry - Electrochemistry Question with Solution | TestHub

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