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ChemistryElectrochemistryConductance/conductivity/^mMedium2 minQB

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Passage / Comprehension

Resistance of a conductivity cell filled with 0.01 M HA (aq.) solution is 200 $Ω$ at 300 K. (HA is a weak monoprotic acid). If the cell constant is 4 cm⁻¹ and Λ⁰_m(HA) is 2 $Ω$ ^-1 m²mol⁻¹. ( $R = 0.08$ bar/mol-K)

Molar conductivity of $0.01 M HA (Ω^{- 1} cm^{2} mol^{- 1})$

Options:

Answer:

Solution:

$Λ_{m}^{0} = K \times \frac{1000}{M} = \frac{1}{R} \times \frac{ℓ}{A} \times \frac{1000}{M}$

$\frac{1}{200} \times \frac{1000}{0.01} \times 4 = 2 \times 1 0^{3} Ω^{- 1} cm^{2} mol^{- 1}$

Stream:JEESubject:ChemistryTopic:ElectrochemistrySubtopic:Conductance/conductivity/^m

⏱ 2mℹ️ Source: QB

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