Chemistry - Electrochemistry Question with Solution | TestHub
ChemistryElectrochemistryKohlrausch's LawMedium2 minQB
ChemistryMediumsingle choice
The conductivity of 0.1 M ethanoic acid is 0.039 S . Then the degree of dissociation of ethanoic acid is:
Given = 350 S ; = 40 S
Options:
Answer:
B
Solution:
κ = 0.039 S/m = 3.9× S/cm. = κ×1000/C = 3.9××1000/0.1 = 3.9 S .
= 350 + 40 = 390.
α = 3.9/390 = 0.01 = .
Answer: (B).
Stream:JEESubject:ChemistryTopic:ElectrochemistrySubtopic:Kohlrausch's Law
⏱ 2mℹ️ Source: QB
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