Chemistry - Electrochemistry Question with Solution | TestHub

ChemistryElectrochemistryKohlrausch's LawMedium2 minQB
ChemistryMediumsingle choice

The conductivity of 0.1 M ethanoic acid is 0.039 S . Then the degree of dissociation of ethanoic acid is:

Given = 350 S ; = 40 S

Options:

Answer:
B
Solution:

κ = 0.039 S/m = 3.9× S/cm. = κ×1000/C = 3.9××1000/0.1 = 3.9 S .

= 350 + 40 = 390.

α = 3.9/390 = 0.01 = .

Answer: (B).

Stream:JEESubject:ChemistryTopic:ElectrochemistrySubtopic:Kohlrausch's Law
⏱ 2mℹ️ Source: QB

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