Chemistry - Electrochemistry Question with Solution | TestHub

During an electrolysis of conc. ${\mathrm{H}}_2{\mathrm{SO}}_4$, perdisulphuric acid $\left({\mathrm{H}}_2{\mathrm{S}}_2{\mathrm{O}}_8\right)$ and ${\mathrm{O}}_2$ form at anode in equimolar amount. The mole of ${\mathrm{H}}_2$ that will form simultaneously at other electrode will be X times of ${\mathrm{O}}_2$. What is the value of X ?

(Given : 2H₂SO₄ → H₂S₂O₈ + 2H⁺ + 2e^- )