If E Fe 2 + / Fe ∘ is X 1 , E Fe 3 + / Fe ∘ is X 2 , then E Fe 3 + / Fe 2 + ∘ will be

Δ G 3 = Δ G 2 − Δ G 1 − n 3 F E 3 ∘ = − n 2 F E 2 ∘ − ( − n 1 F E 1 ∘ ) E 3 ∘ = n 3 F n 2 F E 2 ∘ − n 1 F E 1 ∘ = n 3 n 2 E 2 ∘ − n 1 E 1 ∘ E 3 ∘ = 3 X 2 − 2 X 1

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ChemistryElectrochemistryRelationship between Eº, DGº & KeqMedium2 minQB

ChemistryMediumsingle choice

If $E_{Fe^{2 +} / Fe}^{\circ}$ is $X_{1}, E_{Fe^{3 +} / Fe}^{\circ}$ is $X_{2}$ , then $E_{Fe^{3 +} / Fe^{2 +}}^{\circ}$ will be

Options:

Answer:

Solution:

$Δ G_{3} = Δ G_{2} - Δ G_{1}$

$- n_{3} F E_{3}^{\circ} = - n_{2} F E_{2}^{\circ} - (- n_{1} F E_{1}^{\circ})$

$E_{3}^{\circ} = \frac{n _{2} F E _{2}^{\circ} - n _{1} F E _{1}^{\circ}}{n _{3} F} = \frac{n _{2} E _{2}^{\circ} - n _{1} E _{1}^{\circ}}{n _{3}}$

$E_{3}^{\circ} = 3 X_{2} - 2 X_{1}$

Stream:JEESubject:ChemistryTopic:ElectrochemistrySubtopic:Relationship between Eº, DGº & Keq

⏱ 2mℹ️ Source: QB

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