Chemistry - Electrochemistry Question with Solution | TestHub

Cu²⁺ + 2e⁻ → Cu; $E^{\circ }=0.337V$ …(1)

Therefore, $-\Delta G^{\circ }=2\times 0.337\times F$

Cu²⁺ + e⁻ → Cu⁺; $E^{\circ }=0.153V$ …(2)

Therefore, $-\Delta G^{\circ }=0.153\times 1\times F$

Subtracting equation (1) and (2), we get:

Cu⁺ + e⁻ → Cu; $-\Delta G^{\circ }=0.521F$

Since $-\Delta G^{\circ }=nF{E}^{\circ }$,

$0.521F=1\times F\times E^{\circ }$

Therefore, $E^{\circ }=0.521V$.