Chemistry - Electrochemistry Question with Solution | TestHub

ChemistryElectrochemistryFaraday's Law of Electrolysis/Electrolytic CellsMedium2 minQB

ChemistryMediumsingle choice

During the electrolysis of aqueous $CuSO_{4}$ solution using platinum electrodes:

Answer:

Solution:

Cathode: $Cu^{2 +} + 2 e^{-} \to Cu$ (Cu, not $H_{2}$ , is formed since $E^{\circ}$ = 0.34 V is higher than that of $H^{+}$ ).

Anode: $2 H_{2} O \to O_{2} + 4 H^{+} + 4 e^{-}$ , so $O_{2}$ is evolved and the solution becomes acidic (not alkaline).

Answer: (C).

Stream:JEESubject:ChemistryTopic:ElectrochemistrySubtopic:Faraday's Law of Electrolysis/Electrolytic Cells

⏱ 2mℹ️ Source: QB

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