What must be the molarity of BaCl 2 solution to have molar conductivity 240 Ω − 1 cm 2 mol − 1 and conductivity 0.012 Ω − 1 cm − 1 at 2 5 ∘ C ?

Question

What must be the molarity of BaCl 2 ​ solution to have molar conductivity 240 Ω − 1 cm 2 mol − 1 and conductivity 0.012 Ω − 1 cm − 1 at 2 5 ∘ C ?

TestHub · Accepted Answer

The relationship between molar conductivity $Λ_{m}$ , conductivity $κ$ , and molarity $M$ is given by the formula:

$Λ_{m} = \frac{κ \times 1000}{M}$

Given values are:
$Λ_{m} = 240 Ω^{- 1} cm^{2} mol^{- 1}$
$κ = 0.012 Ω^{- 1} cm^{- 1}$

Substituting the given values into the formula:

$240 = \frac{0.012 \times 1000}{M}$

$240 = \frac{12}{M}$

$M = \frac{12}{240}$

$M = 0.05 M$

Answer: $0.05$ M

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