Chemistry - Electrochemistry Question with Solution | TestHub

The standard cell potential is given by the difference between the standard reduction potentials of the cathode and the anode.

$E_{\text{cell}}^0=E_{\text{cathode}}^0-E_{\text{anode}}^0$

From the given cell representation, aluminium (Al) undergoes oxidation and acts as the anode, while lead (Pb) undergoes reduction and acts as the cathode.

$E_{\text{cell}}^0=E_{{\text{Pb}}^{2+}/\text{Pb}}^0-E_{{\text{Al}}^{3+}/\text{Al}}^0$

Substituting the given values:

$1.5=-0.14-E_{{\text{Al}}^{3+}/\text{Al}}^0$

$E_{{\text{Al}}^{3+}/\text{Al}}^0=-0.14-1.5=-1.64\text{ V}$

Answer: $-1.64$ V