Standard electrode potential of three metals X, Y and Z are − 1.2 V, + 0.5 V and − 3.0 V respectively. The reducing power of these metals will be

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Standard electrode potential generally refers to the standard reduction potential.

A lower (more negative) standard reduction potential indicates a greater tendency for the metal to get oxidized, which means it acts as a stronger reducing agent.

The given standard reduction potentials are:
$E_{X}^{\circ} = - 1.2$ V
$E_{Y}^{\circ} = + 0.5$ V
$E_{Z}^{\circ} = - 3.0$ V

Comparing the values, we have $- 3.0 V < - 1.2 V < + 0.5 V$ .

Since $Z$ has the most negative standard reduction potential, it is the strongest reducing agent, followed by $X$ and then $Y$ .

Therefore, the order of reducing power is $Z > X > Y$ .

Answer: $Z > X > Y$

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