Chemistry - Electrochemistry Question with Solution | TestHub

Given conductivity $\kappa =8\times 10^{-5}{\text{ohm}}^{-1}{\text{cm}}^{-1}$

Concentration $C=0.02\text{M}$

Molar conductivity ${\Lambda }_m=\frac{\kappa \times 1000}{C}$

${\Lambda }_m=\frac{8\times 10^{-5}\times 1000}{0.02}$

${\Lambda }_m=\frac{8\times 10^{-2}}{2\times 10^{-2}}$

${\Lambda }_m=4{\text{ohm}}^{-1}{\text{cm}}^2{\text{mol}}^{-1}$

Answer: $4{\text{ohm}}^{-1}{\text{cm}}^2{\text{mol}}^{-1}$