Chemistry - Electrochemistry Question with Solution | TestHub

The standard EMF of the cell is given by $E_{\text{cell}}^{\circ }=E_{\text{cathode}}^{\circ }-E_{\text{anode}}^{\circ }$.

From the cell representation, copper is at the cathode and nickel is at the anode.

$E_{\text{cell}}^{\circ }=E_{{\text{Cu}}^{2+}/\text{Cu}}^{\circ }-E_{{\text{Ni}}^{2+}/\text{Ni}}^{\circ }$

Substituting the given values:

$0.59=0.34-E_{{\text{Ni}}^{2+}/\text{Ni}}^{\circ }$

$E_{{\text{Ni}}^{2+}/\text{Ni}}^{\circ }=0.34-0.59=-0.25\text{ V}$

Answer: $-0.25$ volt