Chemistry - Electrochemistry Question with Solution | TestHub

The cell constant $G^{\ast }$ is related to conductivity $\kappa$ and resistance $R$ by the formula:

$G^{\ast }=\kappa \times R$

Given:
$\kappa =2\times 10^{-3}{\Omega }^{-1}{\text{cm}}^{-1}$
$R=90\Omega$

Substituting the values:

$G^{\ast }=(2\times 10^{-3})\times 90$

$G^{\ast }=180\times 10^{-3}{\text{cm}}^{-1}$

$G^{\ast }=0.18{\text{cm}}^{-1}$

Answer: $0.18{\text{cm}}^{-1}$