Chemistry - Electrochemistry Question with Solution | TestHub

The degree of dissociation $\alpha$ is given by the ratio of molar conductivity at a given concentration to the molar conductivity at infinite dilution (zero concentration).

$\alpha =\frac{{\Lambda }_m}{{\Lambda }_m^{\circ }}$

Given:
${\Lambda }_m=16.5{\Omega }^{-1}{\mathrm{cm}}^2{\mathrm{mol}}^{-1}$
${\Lambda }_m^{\circ }=390.7{\Omega }^{-1}{\mathrm{cm}}^2{\mathrm{mol}}^{-1}$

Substituting the values:

$\alpha =\frac{16.5}{390.7}$

$\alpha =0.0422$

Answer: 0.0422