Chemistry - Electrochemistry Question with Solution | TestHub

The relation between cell constant ($G^{\ast }$), resistance ($R$), and conductivity ($\kappa$) is given by:

$G^{\ast }=\kappa \times R$

Given:
Resistance, $R=115\Omega$
Conductivity, $\kappa =1.90\times 10^{-3}{\text{S cm}}^{-1}$

Substituting the given values into the formula:

$G^{\ast }=(1.90\times 10^{-3}{\text{S cm}}^{-1})\times (115\Omega )$

$G^{\ast }=218.5\times 10^{-3}{\text{cm}}^{-1}$

$G^{\ast }=0.2185{\text{cm}}^{-1}$

Rounding off to three decimal places, the cell constant is $0.218{\text{cm}}^{-1}$.

Answer: $0.218{\mathrm{cm}}^{-1}$