Conductivity of a solution is 1.26 × 1 0 − 2 Ω − 1 cm − 1 . Calculate molar conductivity for 0.01 M solution.

Λ = c 1000 k = 0.01 mol L − 1 1000 cm 3 L − 1 × 1.26 × 1 0 − 2 Ω − 1 cm − 1 = 1.26 × 1 0 3 Ω − 1 cm 2 mol − 1

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ChemistryElectrochemistryConductance/conductivity/^mMedium2 minPYQ_2023

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Conductivity of a solution is $1.26 \times 1 0^{- 2} Ω^{- 1} cm^{- 1}$ . Calculate molar conductivity for $0.01 M$ solution.

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Answer:

Solution:

$Λ = \frac{1000 k}{c} = \frac{1000 cm ^{3} L ^{- 1} \times 1.26 \times 1 0 ^{- 2} Ω ^{- 1} cm ^{- 1}}{0.01 mol L ^{- 1}} = 1.26 \times 1 0^{3} Ω^{- 1} cm^{2} mol^{- 1}$

Stream:MHT_CETSubject:ChemistryTopic:ElectrochemistrySubtopic:Conductance/conductivity/^m

⏱ 2mℹ️ Source: PYQ_2023

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