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ChemistryElectrochemistryConductance/conductivity/^mMedium2 minPYQ_2023

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What is the molar concentration of acetic acid if value of its dissociation constant is $1.8 \times 1 0^{- 5}$ and degree of dissociation is 0.02 ?

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Answer:

Solution:

$K_{a} = 1.8 \times 1 0^{- 5}; α = 0.02$ For a weak monobasic acid, $K_{a} = α^{2} c$ $∴ c = \frac{K _{a}}{α ^{2}} = \frac{1.8 \times 1 0 ^{- 5}}{0.0 2 ^{2}} = 0.045 M = 4.5 \times 1 0^{- 2} M$

Stream:MHT_CETSubject:ChemistryTopic:ElectrochemistrySubtopic:Conductance/conductivity/^m

⏱ 2mℹ️ Source: PYQ_2023

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