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Chemistry - Electrochemistry Question with Solution | TestHub

ChemistryElectrochemistryGalvanic cells/Nernst Equation/Concentration CellsMedium2 minPYQ_2022

ChemistryMediumsingle choice

What is the change in potential of following cell $Zn (s) Zn n^{2 +} 1 M Pb^{2 +} 1 M ∣ Pb (s)$ if concentration of ions at anode is increased 10 times?

Options:

Answer:

Solution:

$E_{cell} = E_{cell}^{0} - \frac{0.0591}{2} lo g \frac{[ Zn ^{+ 2} ]}{[ Pb ^{+ 2} ]}$ As conc. of $Zn^{+ 2}$ increases 10 times, $E_{cell}$ decreases by 0.0296 volts.

Stream:MHT_CETSubject:ChemistryTopic:ElectrochemistrySubtopic:Galvanic cells/Nernst Equation/Concentration Cells

⏱ 2mℹ️ Source: PYQ_2022

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