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ChemistryElectrochemistryConductance/conductivity/^mEasy2 minPYQ_2021

ChemistryEasysingle choice

The conductivity of $0.3 M$ solution of $KCl$ at $298 K$ is $0.0627 S cm^{1}$ . What is its molar conductivity?

Answer:

Solution:

$Λ_{m} = \frac{k \times 1000}{M} k = 0.0627 S cm^{1} M = 0.3 = \frac{0.0627 \times 1000}{0.3} = 209 S cm^{2} mol^{- 1}$

Stream:MHT_CETSubject:ChemistryTopic:ElectrochemistrySubtopic:Conductance/conductivity/^m

⏱ 2mℹ️ Source: PYQ_2021

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