Chemistry - Electrochemistry Question with Solution | TestHub

For the cell $\mathrm{Cu}\left(\mathrm{s}\right)\left|{\mathrm{Cu}}^{2+}\left(\mathrm{aq}\right)(0.1\mathrm{M})\Vert {\mathrm{Ag}}^{+}\left(\mathrm{aq}\right)(0.01\mathrm{M})\right|\mathrm{Ag}\left(\mathrm{s}\right)$ the cell potential ${\mathrm{E}}_1=0.3095 \mathrm{V}$. For the cell $\mathrm{Cu}\left(\mathrm{s}\right)\left|{\mathrm{Cu}}^{2+}\left(\mathrm{aq}\right)(0.01\mathrm{M})\Vert {\mathrm{Ag}}^{+}\left(\mathrm{aq}\right)(0.001\mathrm{M})\right|\mathrm{Ag}\left(\mathrm{s}\right)$ the cell potential $=\mathrm{x}\times {10}^{-2} \mathrm{V}.$ Find value of x (Round off the Nearest Integer).

[ Use $:\frac{2.303\mathrm{RT}}{\mathrm{F}}=0.059 \mathrm{J}$ ]