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ChemistryElectrochemistryMiscellaneous/MixedEasy2 minPYQ_2020

ChemistryEasysingle choice

Determine the value of the equilibrium constant for the reaction
$2 B r^{-} (a q) + I_{2} (s) ⇌ B r_{2} (l) + 2 I^{-} (a q)$
$E_{c e l l}^{o} = - 0.54 V$

Options:

Answer:

Solution:

The relation between equilibrium constant (K) and $E_{c e l l}^{o}$ is given as
$\log K = \frac{E_{c e l l}^{o} . n}{0.059 V}$
here, n = 2
$= \frac{- 0.54 V \times 2}{0.059 V}$
$= \frac{- 1.08}{0.059} = - 18.3$
On taking antilog
$K = 5.01 \times 1 0^{- 19}$

Stream:NTA_ABHYASSubject:ChemistryTopic:ElectrochemistrySubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

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