Chemistry - Electrochemistry Question with Solution | TestHub

Given that :${\mathrm{E}}_{{\mathrm{O}}_2/{\mathrm{H}}_2\mathrm{O}}^{°}=+1.23\mathrm{V}$,

${\mathrm{E}}_{{\mathrm{S}}_2{\mathrm{O}}_8^{2-}/\text{S}{\text{O}}_4^{2-}}^{°}=+2.05\mathrm{V}$

${\mathrm{E}}_{\text{B}{\text{r}}_2/\text{B}{\text{r}}^{-}}^{°}=+1.09\mathrm{V}$

${\mathrm{E}}_{\text{A}{\text{u}}^{3+}/\text{Au}}^{°}=+1.4\mathrm{V}$

The strongest oxidizing agent is