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Chemistry - Electrochemistry Question with Solution | TestHub

ChemistryElectrochemistryConductance/conductivity/^mEasy2 minPYQ_2020

ChemistryEasysingle choice

Calculate the equivalent conductance of the electrolytic cell.
Given: $l/a = 0 .5 {cm}^{- 1}, R = 50 ohm, N = 1 .0$

Options:

Answer:

Solution:

$l/a = 0 .5 {cm}^{- 1}, R = 50 ohm$
$ρ = \frac{Ra}{l} = \frac{50}{0.5} = 100$
$Λ = k \times \frac{1000}{N} = \frac{1}{ρ} \times \frac{1000}{N} = \frac{1}{100} \times \frac{1000}{1}$
$10 {ohm}^{- 1} {cm}^{2} g {eq}^{- 1}$

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:ElectrochemistrySubtopic:Conductance/conductivity/^m

⏱ 2mℹ️ Source: PYQ_2020

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