Chemistry - Electrochemistry Question with Solution | TestHub

Given, current = 241.25 C

We know that 1 C electricity will deposit$1.118\mathrm{ }\times \mathrm{ }{10}^{-3}\mathrm{g}$of silver.

∴ 241.25 C electricity will deposit

$=\mathrm{ }(1.118\mathrm{ }\times \mathrm{ }{10}^{-3})\mathrm{ }\times \mathrm{ }241.25$

= 0.27 g of silver.