Chemistry - Electrochemistry Question with Solution | TestHub

Anode:-$2{\text{H}}_{\text{2}}\text{O}\to {\text{O}}_2+4{\text{H}}^{+}+4{\text{e}}^{-}$
Cathode:-${\text{Cu}}^{+2}\left(\text{aq}\right)+2{\text{e}}^{-}\to \text{Cu}\left(\text{s}\right)$
Solution will left with${\text{SO}}_4^{-2}$$\&{\text{H}}^{+}$ions
So, we can say it is aq solutions of${\text{H}}_2{\text{SO}}_4$