Chemistry - Electrochemistry Question with Solution | TestHub

$\text{Zn(s)}\text{+}{\text{2H}}^{\text{+}}\text{(aq)}\to {\text{Zn}}^{\text{2+}}\text{(aq)}\text{+}{\text{H}}_{\text{2}}\text{(g)}$
${\text{E}}_{\text{ cell}}\text{=}{\text{E}}_{\text{ cell}}^{\text{o}}-\frac{\text{0}\text{.059}}{\text{2}}\text{ log}\frac{\left[{\text{Zn}}^{\text{2+}}\right]\text{×}{\text{p}}_{{\text{H}}_{\text{2}}}}{{\left[{\text{H}}^{\text{+}}\right]}^{\text{2}}}$
On adding${\text{H}}_2{\text{SO}}_4$, the$\left[{\text{H}}^{+}\right]$will increase therefore${\text{E}}_{\text{ cell}}$will also increase and the equilibrium will shift towards the right.