Chemistry - Electrochemistry Question with Solution | TestHub

ChemistryElectrochemistryGalvanic cells/Nernst Equation/Concentration CellsEasy2 minPYQ_2020

ChemistryEasysingle choice

3 Faradays of electricity was passed through an aqueous solution of iron (II) bromide. The weight of iron metal (at. wt. = 56) deposited at the cathode (in g) is

Options:

Answer:

Solution:

${F e}^{2 +} + 2 e^{-} \to F e$

$E_{F e} = \frac{56}{2} = 28$

$w_{F e} = E_{F e} \times$ number of Faraday

$= 28 \times 3 = 84 g$

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:ElectrochemistrySubtopic:Galvanic cells/Nernst Equation/Concentration Cells

⏱ 2mℹ️ Source: PYQ_2020

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