Chemistry - Electrochemistry Question with Solution | TestHub

$\text{Fe(s)}\to {\text{Fe}}^{\text{2+}}\text{+}{\text{2e}}^{-}\text{;}{\text{ΔG}}_{\text{1}}^{\text{o}}$
${\text{2H}}^{\text{+}}\text{+}{\text{2e}}^{-}\text{+}\frac{\text{1}}{\text{2}}{\text{O}}_{\text{2}}\to {\text{H}}_{\text{2}}\text{O(l);}{\text{ΔG}}_{\text{2}}^{\text{o}}$
$\text{Fe(s)}\text{+}{\text{2H}}^{\text{+}}\text{+}\frac{\text{1}}{\text{2}}{\text{O}}_{\text{2}}\to {\text{Fe}}^{\text{2+}}\text{+}{\text{H}}_{\text{2}}\text{O;}{\text{ΔG}}_{\text{3}}^{\text{o}}$
Applying,${\text{ΔG}}_{\text{1}}^{\text{o}}\text{+}{\text{ΔG}}_{\text{2}}^{\text{o}}\text{=}{\text{ΔG}}_{\text{3}}^{\text{o}}$
${\text{ΔG}}_{\text{3}}^{\text{o}}\text{=}\left(-\text{2F}\times \text{0}\text{.44}\right)\text{+}\left(-\text{2F}\text{×}\text{1}\text{.23}\right)$
${\text{ΔG}}_{\text{3}}^{\text{o}}\text{=}\left(-\text{2}\text{×}\text{96500}\text{×}\text{0}\text{.44}\right)\text{+}\left(-\text{2}\text{×}\text{96500}\text{×}\text{1}\text{.23}\right)$
${\text{ΔG}}_{\text{3}}^{\text{o}}\text{=}-\text{322310}\text{J}$
$\therefore {\text{ΔG}}_{\text{3}}^{\text{o}}=-322\text{kJ}$