Molar conductivity of 0.01 M HCl solution is 400 ⋅ 0 Ω − 1 cm 2 mol − 1 . Calculate the conductivity of HCl solution.

C = 0.01 M , ∧ = 400.0 Ω − 1 cm 2 mol − 1 k = ? ∧ = C 1000 k ∴ k = 1000 ∧× C ∴ k = 1000 400.0 × 0.01 = 4.0 × 1 0 − 3 Ω − 1 cm − 1

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ChemistryElectrochemistryConductance/conductivity/^mMedium2 minPYQ_2020

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Molar conductivity of $0.01$ M HCl solution is $400 \cdot 0 Ω^{- 1} cm^{2} mol^{- 1}$ . Calculate the conductivity of $HCl$ solution.

Options:

Answer:

Solution:

$C = 0.01 M, \land = 400.0 Ω^{- 1} cm^{2} mol^{- 1}$ $k = ?$ $\land = \frac{1000 k}{C} ∴ k = \frac{\land\times C}{1000}$ $∴ k = \frac{400.0 \times 0.01}{1000} = 4.0 \times 1 0^{- 3} Ω^{- 1} cm^{- 1}$

Stream:MHT_CETSubject:ChemistryTopic:ElectrochemistrySubtopic:Conductance/conductivity/^m

⏱ 2mℹ️ Source: PYQ_2020

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