Chemistry - Electrochemistry Question with Solution | TestHub

Hydrolysis of water can be represented by the following equations

${2\mathrm{H}}_2\mathrm{O}\mathrm{ }\rightleftharpoons \mathrm{ }{\mathrm{O}}_2+\mathrm{ }{4\mathrm{H}}^{+}+\mathrm{ }{4e}^{-}$

∵ 4 Faraday of charge liberate${\mathrm{O}}_2\mathrm{ }=\mathrm{ }32\mathrm{ }\mathrm{g}$

∴ 1 Faraday of charge liberate${\mathrm{O}}_2\mathrm{ }=\frac{32}{4}\mathrm{ }\mathrm{ }\mathrm{g}$

= 8 g