Chemistry - Electrochemistry Question with Solution | TestHub

One millimole $=0.001\mathrm{mol}$ i.e. $1\times 10^{-3}\mathrm{mol}$ $\because 96500\mathrm{C}$ is required for $1\mathrm{mol}$ of electrons. $\therefore 193\mathrm{C}$ give $\frac{193\times 1}{96500}=0.002\mathrm{mol},$ i.e. $2\times 10^{-3}\mathrm{mol}$ of electrons. Thus, value of $n$ in $M^{n+}$ is $=\frac{0.002}{0.001}=2$ Hence, option (b) is the correct answer.