Chemistry - Electrochemistry Question with Solution | TestHub

The cell reaction is $\mathrm{Zn}+{\mathrm{Fe}}^{2+}⟶{\mathrm{Zn}}^{2+}+\mathrm{Fe}$ From Nernst equation $\begin{array}{rl}& {\mathrm{E}}_{\text{cell }}={\mathrm{E}}_{\text{cell }}^{\circ }-\frac{0.0591}{\mathrm{n}}\log \frac{{\mathrm{a}}_{{\mathrm{Zn}}^{2+}}}{{\mathrm{a}}_{{\mathrm{Fe}}^{2+}}}\\ & =(0.763-0.44)-\frac{0.0591}{1}\log \frac{0.001}{0.005}\\ & =0.364\mathrm{V}\\ & \end{array}$