Chemistry - Electrochemistry Question with Solution | TestHub

Higher the electrode potential, better is the oxidising agent. Since, the electrode potential decreases in the order : ${\mathrm{Ag}}^{+}\left|\mathrm{Ag}(+0.80\mathrm{V})>{\mathrm{Fe}}^{3+}\right|{\mathrm{Fe}}^{2+}(+0.77\mathrm{V})>$ ${\mathrm{I}}_{2(s)}\left|{\mathrm{I}}^{-}(+0.54\mathrm{V})>{\mathrm{Cu}}^{2+}\right|\mathrm{Cu}(+0.34\mathrm{V})$ Hence, ${\mathrm{Ag}}^{+}$is the strongest oxidising agent.