Chemistry - Electrochemistry Question with Solution | TestHub

In the electrochemical cell:

$\mathrm{Zn}\left|{\mathrm{ZnSO}}_4\left(0.01\mathrm{M}\right)\right|\left|{\mathrm{CuSO}}_4\left(1.0\mathrm{ }\mathrm{M}\right)\right|\mathrm{Cu},$the emf of this Daniel cell is${\mathrm{E}}_1$. When the concentration${\mathrm{ZnSO}}_4$is changed to$1.0\mathrm{M}$and that of${\mathrm{CuSO}}_4$changed to$0.01\mathrm{M},$the emf changes to${\mathrm{E}}_2$. From the following, which one is the relationship between${\mathrm{E}}_1$and${\mathrm{E}}_2$? (Given,$\frac{\mathrm{RT}}{\mathrm{F}}=0.059$)NEET 2017