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ChemistryElectrochemistryGalvanic cells/Nernst Equation/Concentration CellsMedium2 minPYQ_2016

ChemistryMediumsingle choice

The EMF of the cell $Tl / Tl^{+} (0.001 M) ∥ Cu^{2 +}$ $(0.01 M) / Cu$ is $0.83.$ The cell EMF can be increased by

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Answer:

Solution:

The oxidation potential $\propto \frac{1}{Concentration of ions}$ and reduction potential $\propto$ concentration of ions. The cell voltage can be increased by decreasing the concentration of ions around anode or by increasing the concentration of ions around cathode

Stream:BITSATSubject:ChemistryTopic:ElectrochemistrySubtopic:Galvanic cells/Nernst Equation/Concentration Cells

⏱ 2mℹ️ Source: PYQ_2016

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