Chemistry - Electrochemistry Question with Solution | TestHub

From the Faradiay's IInd law, we know that $$W\propto \text{ Zit, }W\propto \frac{E}{96500}it$$ or it $\propto \frac{1}{E}$ or electricity $\propto \frac{1}{E}$ Thus, the amount of electricity required for ${\mathrm{ZnSO}}_4,{\mathrm{AlCl}}_3$ and ${\mathrm{AgNO}}_3$ is in the ratio of 2: 3: 1 . (Here, 2,3 and 1 are the valencies of metal atom in the given compounds). Alternatively In $ZnS{O}_4$, $Z{n}^{2+}+2e^{-}$ $\to Z\mathrm{n}$ $1mol$ $\text{2 mol or 2 Faraday}$ In ${\mathrm{AlCl}}_3$, ${\mathrm{Al}}^{3+}+3e^{-}⟶\mathrm{Al}$ $1mol$ $\text{3F}$ In ${\mathrm{AgNO}}_3$, ${\mathrm{Ag}}^{+}+e^{-}⟶\mathrm{Ag}$ $1mol$ $\text{1F}$ Thus, the ratio of amounts of electricity required is 2: 3: 1